Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. (i) 26 and 91 (ii) 510 and 92 (iii) 336 and 54

Asked on 2024-05-31 12:17:51 by Somu | Votes 30 | Views: 2465 | Tags: | Last Updated: 2024-05-31 22:49:35

Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers.

(i) 26 and 91

(ii) 510 and 92

(iii) 336 and 54

Somu · Answer 1 · 2024-06-01 04:30:36

29 vote

Answered by Somu on 2024-06-01 04:30:36 | Votes 29 | # | Last Updated: 2024-06-01 15:01:04

1. $26$ and $91$

Factors of above numbers are:

$26 = 2 \times 13$

$91 = 7 \times 13$

Common factors are: 13

Hence HCF is: $13$

LCM is: $13 \times 2 \times 7 = 182$

Somu · Answer 2 · 2024-06-01 05:30:42

20 vote

Answered by Somu on 2024-06-01 05:30:42 | Votes 20 | #

2. $510$ and $92$

$92 = 2×2×23$

$510 = 2×3×5×17$

Common Factors are: $2$

Hence HCF is $2$

LCM = $2^2 \times 3 \times 5 \times 17 \times 23 = 23460$

Somu · Answer 3 · 2024-06-01 05:33:32

3. $336$ and $54%

$336 = 2 × 2 × 2 × 2 × 3 × 7$

$54 = 2 × 3 × 3 × 3$

Highest Common Factor: $2 \times 3$

Hence HCF = $6$

LCM Would be $= 2^4 \times 3 \times 7 \times 2 \times 3 \times 3 \times 3 = 3024$

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