Jar A contains 78 litres of milk and water in the respective ratio of 6 : 7. 26 litres of the mixture was taken out from Jar A. What quanti…
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Jar A contains 78 litres of milk and water in the respective ratio of 6 : 7. 26 litres of the mixture was taken out from Jar A. What quantity of milk should be added to jarA, so that water constitutes 40% of the resultant mixture in jar A?
Solution
Jar A has 78 litres of mixture of milk and water in the respective ratio of 6 : 7
=> Quantity of milk in Jar A = $\frac{6}{13} \times 78 = 36$ litres
Quantity of water in Jar A = $78 - 36 = 42$ litres
26 litres of the mixture was taken out from Jar A, i.e., $\frac{26}{78} = (\frac{1}{3})^{rd}$
=> Milk left = $36 - \frac{1}{3} \times 36 = 24$
Water left = $42 - \frac{1}{3} \times 42 = 28$
Let milk added to jar A = $x$ litres
Acc. to ques, => $\frac{24 + x}{28} = \frac{60}{40}$