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Jar A has 60 litres of mixture of milk and water in the respective ratio of 2 : 1. Jar B which had 40 litres of mixture of milk and water w…

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Jar A has 60 litres of mixture of milk and water in the respective ratio of 2 : 1. Jar B which had 40 litres of mixture of milk and water was emptied into jar A, as a result in jar A, the respective ratio of milk and water became 13 : 7. What was the quantity of water in jar B?
  • A8 litres
  • B15 litres
  • C22 litres
  • D7 litres
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Solution
Jar A has 60 litres of mixture of milk and water in the respective ratio of 2 : 1
=> Quantity of milk in Jar A = $\frac{2}{3} \times 60 = 40$ litres
Quantity of water in Jar A = $60 - 40 = 20$ itres
Let quantity of water in Jar B = $x$ litres
=> Quantity of milk in Jar B = $(40 - x)$ litres
Acc. to ques, => $\frac{40 + (40 - x)}{20 + x} = \frac{13}{7}$
=> $560 - 7x = 260 + 13x$
=> $13x + 7x = 560 - 260$
=> $20x = 300$
=> $x = \frac{300}{20} = 15$ litres