1
In each of the following questions, two equations I and II have been given.
Solve these questions and answer
Solve these questions and answer
- Aif x < y
- Bif x ? y
- Cif x = y or the relation cannot be established
- Dif ? y
- Eif x > y
Answer not set
Discussion 1
Log in or create a free account to reply and vote.
0
CCommunity
Solution
Statement I : $9x^{2}+3x-2=0$
=> $9x^2 + 6x - 3x - 2 = 0$
=> $3x (3x + 2) - 1 (3x + 2) = 0$
=> $(3x - 1) (3x + 2) = 0$
=> $x = \frac{1}{3} , \frac{-2}{3}$
Statement II : $8y^{2}+6y+1=0$
=> $8y^2 + 4y + 2y + 1 = 0$
=> $4y (2y + 1) + 1 (2y + 1) = 0$
=> $(4y + 1) (2y + 1) = 0$
=> $y = \frac{-1}{4} , \frac{-1}{2}$
$\therefore$ No relation can be established.
Statement I : $9x^{2}+3x-2=0$
=> $9x^2 + 6x - 3x - 2 = 0$
=> $3x (3x + 2) - 1 (3x + 2) = 0$
=> $(3x - 1) (3x + 2) = 0$
=> $x = \frac{1}{3} , \frac{-2}{3}$
Statement II : $8y^{2}+6y+1=0$
=> $8y^2 + 4y + 2y + 1 = 0$
=> $4y (2y + 1) + 1 (2y + 1) = 0$
=> $(4y + 1) (2y + 1) = 0$
=> $y = \frac{-1}{4} , \frac{-1}{2}$
$\therefore$ No relation can be established.