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The present ages of Trisha and Shalini are in the ratio of 7: 6 respectively . After 8 years the ratio of their ages will be 9 : 8. What is the difference in their ages ?
- A4 years
- B8 years
- C10 years
- D12 years
Answer not set
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Solution
Let present ages of Trisha and Shalini be $7x$ and $6x$ years respectively.
Acc. to ques, ratio of their ages after 8 years
=> $\frac{7x + 8}{6x + 8} = \frac{9}{8}$
=> $56x + 64 = 54x + 72$
=> $56x - 54x = 72 - 64$
=> $2x = 8$
=> $x = \frac{8}{2} = 4$
$\therefore$ Difference in their ages = $7x - 6x = x$
= 4 years
Let present ages of Trisha and Shalini be $7x$ and $6x$ years respectively.
Acc. to ques, ratio of their ages after 8 years
=> $\frac{7x + 8}{6x + 8} = \frac{9}{8}$
=> $56x + 64 = 54x + 72$
=> $56x - 54x = 72 - 64$
=> $2x = 8$
=> $x = \frac{8}{2} = 4$
$\therefore$ Difference in their ages = $7x - 6x = x$
= 4 years