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A alone can make 100 baskets in 6 days and B alone can make 100 baskets in 12 days. In how many days can A and B together make 100 baskets?
- A3 days
- B5 days
- C$$2{1 \over 2}$$ days
- D$$3{1 \over 2}$$ days
Answer not set
Discussion 1
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CCommunity
Solution
A alone can make 100 baskets in 6 days and B alone in 12 days
=> Rate of efficiency of A = $\frac{100}{6}$ baskets/day
Rate of efficiency of B = $\frac{100}{12} = \frac{50}{6}$ baskets/day
=> Baskets made by A and B together in 1 day = $\frac{100}{6} + \frac{50}{6}$
= $\frac{150}{6} = 25$ baskets/day
$\therefore$ Time taken by A and B together to make 100 baskets = $\frac{100}{25} = 4$ days
A alone can make 100 baskets in 6 days and B alone in 12 days
=> Rate of efficiency of A = $\frac{100}{6}$ baskets/day
Rate of efficiency of B = $\frac{100}{12} = \frac{50}{6}$ baskets/day
=> Baskets made by A and B together in 1 day = $\frac{100}{6} + \frac{50}{6}$
= $\frac{150}{6} = 25$ baskets/day
$\therefore$ Time taken by A and B together to make 100 baskets = $\frac{100}{25} = 4$ days