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The solution of the differential equation $2ysinx(\frac{dy}{dx})=sin2x-y^{2}cosx$ with $y(\frac{\pi}{2})=1$ is :
- A$y^{2}=sinx$
- B$x^{2}=siny$
- C$y=sin^{2}x$
- D$y^{2}=1+cosx$
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