Question discussion

If (ab + bc + ca) = 19 and (a + b + c) = 8, find the value of (a2 + b2 + c2).

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? (a + b + c)2 = (a2 + b2 + c2) + 2(ab + bc + ca)

Substituting values,

⇒ (8)2 = (a2 + b2 + c2) + 2(19)

⇒ (a2 + b2 + c2) = 64 – 38

∴ (a2 + b2 + c2) = 26