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Two like parallel forces $P$ and $Q (P > Q)$ act on a rigid body. If the force P is displaced parallel to itself through a distance d, then the resultant of the forces $P$ and $Q$ would be shifted by a distance
- A$\frac{P}{{P + Q}}d$
- B$\frac{P}{{P - Q}}d$
- C$\frac{Q}{{P - Q}}d$
- D$\frac{Q}{{Q - P}}d$
Answer not set