CCommunity
a3b - ab3 = ab(a2 – b2) = ab(a + b)(a – b) - - - (1)
a3b2 + a2b3 = a2b2(a + b) - - - (2)
ab(a + b) - - - (3)
From equations (1), (2) and (3), we get,
LCM = ab(a + b) × ab × (a – b) = a2b2(a2 – b2)
∴ LCM of a3b - ab3, a3b2 + a2b3 and ab(a + b) = a2b2(a2 – b2)