CCommunity
We have rms value given by,
$({{\rm{V}}_{{\rm{rms}}}} = \frac{{{{\rm{V}}_{\rm{m}}}}}{{\sqrt 2 }})$
where, ?$({{\rm{V}}_{\rm{m}}})$ is a peak value.
Thus, we have $({{\rm{V}}_{\rm{m}}} = \sqrt 2 {{\rm{V}}_{{\rm{rms}}}})$
Hence, $({{\rm{V}}_{\rm{m}}} = \sqrt 2 \times 100 = 141.4\;{\rm{V}})$