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The r.m.s. value of a sine wave is 100 A. Its peak value is

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We have rms value given by,

$({{\rm{V}}_{{\rm{rms}}}} = \frac{{{{\rm{V}}_{\rm{m}}}}}{{\sqrt 2 }})$

where, ?$({{\rm{V}}_{\rm{m}}})$ is a peak value.

Thus, we have $({{\rm{V}}_{\rm{m}}} = \sqrt 2 {{\rm{V}}_{{\rm{rms}}}})$

Hence, $({{\rm{V}}_{\rm{m}}} = \sqrt 2 \times 100 = 141.4\;{\rm{V}})$