27
If xa.xb.xc = 1, then a3 + b3 + c3 is equal to:
- A9
- Babc
- Ca + b + c
- D3abc
Answer not set
Discussion 1
Log in or create a free account to reply and vote.
0
CCommunity
xa.xb.xc = x0
⇒ xa + b + c = x0
⇒ a + b + c = 0
Now we know that if a + b + c = 0, then
a3 + b3 + c3 = 3abc.
⇒ xa + b + c = x0
⇒ a + b + c = 0
Now we know that if a + b + c = 0, then
a3 + b3 + c3 = 3abc.