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A beaker contains acid and water in the ratio 1 ∶ x. When 300 ml of the previous mixture and 50 ml of water are mixed, the ratio of acid and water becomes 2 ∶ 5. What is the value of x?
- A2
- B1
- C3
- D4
Answer not set
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CCommunity
Quantity of water in 300 ml of mixture = [x/(x + 1)] × 300
When 50 ml of water is mixed in the mixture, ratio of acid and water becomes 2 ? 5
⇒ Quantity of water in in the new mixture = 5/7 × (300 + 50)
⇒ (x/x + 1) × 300 + 50 = 5/7 × (300 + 50)
⇒ (x/x + 1) × 300 = 200
⇒ (x/x + 1) = 2/3
∴ x = 2
When 50 ml of water is mixed in the mixture, ratio of acid and water becomes 2 ? 5
⇒ Quantity of water in in the new mixture = 5/7 × (300 + 50)
⇒ (x/x + 1) × 300 + 50 = 5/7 × (300 + 50)
⇒ (x/x + 1) × 300 = 200
⇒ (x/x + 1) = 2/3
∴ x = 2