25
If P + (1/P) = 8, find the value of P2 + (1/P2)?
- A62
- B64
- C36
- D44
Answer not set
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CCommunity
Given,
⇒ P + (1/P) = 8 ----(1)
Squaring both the side in equation (1), we get
⇒ (P + 1/P)2 = 82
⇒ P2 + (1/P)2 + 2 × P × 1/P = 64
⇒ P2 + (1/P)2 + 2 = 64
⇒ P2 + (1/P)2 = 64 - 2 = 62
⇒ P + (1/P) = 8 ----(1)
Squaring both the side in equation (1), we get
⇒ (P + 1/P)2 = 82
⇒ P2 + (1/P)2 + 2 × P × 1/P = 64
⇒ P2 + (1/P)2 + 2 = 64
⇒ P2 + (1/P)2 = 64 - 2 = 62