Two cars travel from city A to city B at a speed of 30 km/hr and 36 km/hr respectively. If one car takes 3 hours lesser time than the other…

As per the given data,

We know that the distance travelled by the two cars is equal.

Let the time taken by one car be x hours.

Then the time taken by another car be (x – 3) hours

⇒ Distance travelled by first car = speed of first car × time taken by it = 30 × x = 30x

⇒ Distance travelled by second car = speed of second car × time taken by it = 36 × (x – 3) = 36x – 108

By equating both distances, we get

⇒ 30x = 36x – 108

⇒ 6x = 108

⇒ x = 18

⇒ Time taken by the first car is 18 hours

⇒ Distance travelled by the first car = 30 × x = 30 × 18 = 540 km

∴ Distance between city A and city B = 540 km