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Find the greatest number that will divide 149, 247 and 622 leaving remainders 5, 7 and 10 respectively

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The greatest number that will divide 149, 247 and 622 leaving remainder 5, 7 and 10

Factor of (149 – 5) = 144 = 12 × 12

Factor of (247 – 7) = 240 = 12 × 20

Factor of (622 – 10) = 612 = 12 × 51

Such that 12 is the common number and greatest number.