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The ratio of speed of three racers is 3 : 4 : 6. What is the ratio of time taken by the three racers to cover the same distance?
- A3 : 4 : 6
- B6 : 4 : 3
- C4 : 3 : 2
- D2 : 3 : 5
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Let the distance to be covered be y km and the ratio of the speed of the 3 racers = 3z : 4z : 6z
⇒ Time taken = distance covered/speed
⇒ Time taken by 1st racer = y/(3z)
⇒ Time taken by 2nd racer = y/(4z)
⇒ Time taken by 3rd racer = y/(6z)
Ratio of the 3 times periods = y/(3z) : y/(4z) : y/(6z)
⇒ 1/3 : 1/4 : 1/6 = 4/12 : 3/12 : 2/12
⇒ 4 : 3 : 2
⇒ Time taken = distance covered/speed
⇒ Time taken by 1st racer = y/(3z)
⇒ Time taken by 2nd racer = y/(4z)
⇒ Time taken by 3rd racer = y/(6z)
Ratio of the 3 times periods = y/(3z) : y/(4z) : y/(6z)
⇒ 1/3 : 1/4 : 1/6 = 4/12 : 3/12 : 2/12
⇒ 4 : 3 : 2