A man sells two articles. The cost price of the first article is equal to the selling price of the second article. The first article is sol…

Let the cost price of the first article be Rs. ‘x’

But, the first article is sold at a profit of 20%,

⇒$ Selling price of first article = x + 20% of x = x + x/5 = (6/5)x

Now,

Selling price of second article = Cost price of first article = Rs. x

But, the second article is sold at a loss of 20%,

⇒$ (100 - 20)% of Cost price of second article = Selling price

⇒$ 80% of Cost price of second article = Selling price

⇒$ (4/5) × Cost price of second article = x

⇒$ Cost price of second article = (5/4)x

∴ Required ratio = (6x/5) ? (5x/4) = 24 ? 25