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Rajiv celebrated his birthday on 21st April 2011 on Thursday. Next time in which year will he will celebrate his birthday on same date and day?
- A2019
- B2020
- C2021
- D2022
Answer not set
Discussion 1
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CCommunity
Number of odd days in 2011 = 1
Number of odd days from 2011 till 2012 = 1 + 2 (leap year) = 3
Number of odd days from 2011 till 2013 = 3 + 1 = 4
Number of odd days from 2011 till 2014 = 4 + 1 = 5
Number of odd days from 2011 till 2015 = 5 + 1 = 6
Number of odd days from 2011 till 2016 = 6 + 2 (leap year) = 8 = 1 odd day
Number of odd days from 2011 till 2017 = 1 + 1 = 2
Number of odd days from 2011 till 2018 = 2 + 1 = 3
Number of odd days from 2011 till 2019 = 3 + 1 = 4
Number of odd days from 2011 till 2020 = 4 + 2 (leap year) = 6
Number of odd days from 2011 till 2021 = 6 + 1 = 7 = 0 odd days
Hence, calendar of 2022 will be similar to that of 2011.
Hence, Rajiv will celebrate it on same day and date in 2022.
Number of odd days from 2011 till 2012 = 1 + 2 (leap year) = 3
Number of odd days from 2011 till 2013 = 3 + 1 = 4
Number of odd days from 2011 till 2014 = 4 + 1 = 5
Number of odd days from 2011 till 2015 = 5 + 1 = 6
Number of odd days from 2011 till 2016 = 6 + 2 (leap year) = 8 = 1 odd day
Number of odd days from 2011 till 2017 = 1 + 1 = 2
Number of odd days from 2011 till 2018 = 2 + 1 = 3
Number of odd days from 2011 till 2019 = 3 + 1 = 4
Number of odd days from 2011 till 2020 = 4 + 2 (leap year) = 6
Number of odd days from 2011 till 2021 = 6 + 1 = 7 = 0 odd days
Hence, calendar of 2022 will be similar to that of 2011.
Hence, Rajiv will celebrate it on same day and date in 2022.