A dishonest milkman fills up his bucket, which is only 4/7th full of milk, with water. He again removes 3 litres of this mixture from the b… — Answer & Discussion

A dishonest milkman fills up his bucket, which is only 4/7^th full of milk, with water. He again removes 3 litres of this mixture from the bucket and adds an equal quantity of water. If milk is now 40% of the mixture, then what is the capacity of the bucket?

A25 litres
B40 litres
C15 litres
D10 litres

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Discussion 1

CCommunity08 Jun 2019

Let the capacity of bucket be X litres

⇒ Quantity of milk = (4/7)X

⇒ Quantity of water = 1 – (4/7)X = (3/7)X

⇒ If 3 litres mixture is removed, remaining mixture = X – 3

⇒ Now quantity of milk = (4/7) × (X – 3)

⇒ If 3 litres water is added, quantity of water = (3/7) × (X – 3) + 3

⇒ (4/7) × (X – 3) = 40% of X

⇒ (4/7)X – 12/7 = (40/100)X

⇒ {(4/7) – (40/100)}X = 12/7

∴ X = 10 litres