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Siyaram invested equal sum of money in two schemes. Under scheme X, the compound interest rate was 10 p.c.p.a. and under scheme Y, the comp…

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Siyaram invested equal sum of money in two schemes. Under scheme X, the compound interest rate was 10 p.c.p.a. and under scheme Y, the compound interest rate was 12 p.c.p.a. The interest after two years on the sum invested in Scheme X was Rs. 63. How much is the interest earned under Scheme Y after two years?
  • ARs. 77.21
  • BRs. 70.56
  • CRs. 76.32
  • DRs. 79.46
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CCommunity
Let the principal sum = Rs. x

We know the formula for compound interest-

$( \Rightarrow {\rm{CI}} = \left[ {{\rm{P}}\left\{ {{{\left( {1 + \frac{{\rm{r}}}{{100}}} \right)}^t} - 1} \right\}} \right])$Where,

CI = Compound interest

P = Principal

R = Rate of interest

T = Time period

Under scheme X,

C.I. = 10 % p.a.

$(\begin{array}{l} \Rightarrow {\rm{CI}} = \left[ {{\rm{P}}\left\{ {{{\left( {1 + \frac{{\rm{r}}}{{100}}} \right)}^t} - 1} \right\}} \right]\\ \Rightarrow 63 = \left[ {{\rm{x}}\left\{ {{{\left( {1 + \frac{{10}}{{100}}} \right)}^2} - 1} \right\}} \right]\\ \Rightarrow 63 = \left[ {{\rm{x}}\left\{ {{{\left( {\frac{{110}}{{100}}} \right)}^2} - 1} \right\}} \right]\\ \Rightarrow 63 = \left[ {\frac{{21}}{{100}}{\rm{x}}} \right] \end{array})$

⇒ x = Rs. 300

Under scheme Y,

C.I. = 12 % p.a.

$(\begin{array}{l} \Rightarrow {\rm{CI}} = \left[ {{\rm{P}}\left\{ {{{\left( {1 + \frac{{\rm{r}}}{{100}}} \right)}^t} - 1} \right\}} \right]\\ \Rightarrow {\rm{CI}} = \left[ {300\left\{ {{{\left( {1 + \frac{{12}}{{100}}} \right)}^2} - 1} \right\}} \right]\\ \Rightarrow {\rm{CI}} = \left[ {300\left\{ {{{\left( {\frac{{112}}{{100}}} \right)}^2} - 1} \right\}} \right]\\ \Rightarrow {\rm{CI}} = \left[ {300 \times \frac{{2544}}{{10000}}} \right] \end{array})$

⇒ CI = Rs. 76.32