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Calculate the work done to take an object of mass 10 kg to a height of 20 m. (g = 9.8 m/s2).
- A98 J
- B980 J
- C-1960 J
- D19.6 J
Answer not set
Discussion 1
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CCommunity
Given data: m = 10 kg; s = 20 m; g = 9.8 m/s2
F = m.$g
= 10 ×$ (-9.8) (The negative sign is taken because the displacement is opposite to the direction of the force.)
F = -98 N
W = F×$s
= -98×$20
W = -1960 J (The negative sign appears because the direction of the force is opposite to the direction of displacement so that the work done is negative.)
F = m.$g
= 10 ×$ (-9.8) (The negative sign is taken because the displacement is opposite to the direction of the force.)
F = -98 N
W = F×$s
= -98×$20
W = -1960 J (The negative sign appears because the direction of the force is opposite to the direction of displacement so that the work done is negative.)