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If cot(A/2) = x, then the value of x is?
- A√[(1 + cosA)/(1 - cosA)]
- BcosecA - cotA
- C√[(1 - cosA)/2]
- D√[(1 + cosA)/2]
Answer not set
Discussion 1
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CCommunity
As per the given data,
cot (A/2) = x
cos (A/2)/sin (A/2) = x
we know that:
cos2A = (1 + cos 2A)/2
sin2A = (1 – cos 2A)/2
$(\frac{{\surd \left( {\frac{{1\; + \;cosA}}{2}} \right)}}{{\surd \left( {\frac{{1 - cosA}}{2}} \right)}})$ = x
x = $(\frac{{\surd \left( {1\; + \;\cos A} \right)}}{{\surd \left( {1 - \cos A} \right)}})$
cot (A/2) = x
cos (A/2)/sin (A/2) = x
we know that:
cos2A = (1 + cos 2A)/2
sin2A = (1 – cos 2A)/2
$(\frac{{\surd \left( {\frac{{1\; + \;cosA}}{2}} \right)}}{{\surd \left( {\frac{{1 - cosA}}{2}} \right)}})$ = x
x = $(\frac{{\surd \left( {1\; + \;\cos A} \right)}}{{\surd \left( {1 - \cos A} \right)}})$