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20 L of a mixture contains alcohol and water in the ratio 2 : 3. If 4 L of water is mixed in it, the percentage of alcohol in the new mixture will be
- A50
- B25
- C20
- D33.33%
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CCommunity
Amount of alcohol in the mixture = 2/5 × 20 = 8 L
And amount of water in the mixture = 20 – 8 = 12 L
Given, 4 L of water is added. Hence,
Amount of water in the new mixture = 16 L
Hence, the percentage of alcohol in the new mixture = $(\frac{8}{{24}} \times 100 = 33\frac{1}{3}\%)$
And amount of water in the mixture = 20 – 8 = 12 L
Given, 4 L of water is added. Hence,
Amount of water in the new mixture = 16 L
Hence, the percentage of alcohol in the new mixture = $(\frac{8}{{24}} \times 100 = 33\frac{1}{3}\%)$