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What will come in place of the question mark (?) in the following question?
(80 × 0.40)3 ÷ (40 × 1.6) × (128)3 = (2)? + 7
(80 × 0.40)3 ÷ (40 × 1.6) × (128)3 = (2)? + 7
- A23
- B11
- C12
- D18
Answer not set
Discussion 1
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CCommunity
Follow BODMAS rule to solve this question, as per the order given below,
Step-1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket, the BODMAS rule must be followed,
Step-2- Any mathematical 'Of' or 'Exponent' must be solved next,
Step-3-Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,
Step-4-Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated
We have the expression:
⇒ (80 × 0.40)3 ÷ (40 × 1.6) × (128)3 = (2)? + 7
⇒ 323 ÷ 64 × (128)3 = (2)? + 7
(We know that 64 = 32 × 2)
⇒ (323 ÷ 32 × 2) × (128)3 = (2)? + 7
⇒ 512 × (128)3 = (2)? + 7
(We know that 512 = 29 and 128 = 27)
⇒ $({2^9})$ × $({2^{7\; \times 3}})$ = (2)? + 7
⇒ $({2^{30}})$ = (2)? + 7
⇒ $({2^{7\; + \;23}})$ = (2)? + 7
⇒ ? = 23
Step-1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket, the BODMAS rule must be followed,
Step-2- Any mathematical 'Of' or 'Exponent' must be solved next,
Step-3-Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,
Step-4-Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated
We have the expression:
⇒ (80 × 0.40)3 ÷ (40 × 1.6) × (128)3 = (2)? + 7
⇒ 323 ÷ 64 × (128)3 = (2)? + 7
(We know that 64 = 32 × 2)
⇒ (323 ÷ 32 × 2) × (128)3 = (2)? + 7
⇒ 512 × (128)3 = (2)? + 7
(We know that 512 = 29 and 128 = 27)
⇒ $({2^9})$ × $({2^{7\; \times 3}})$ = (2)? + 7
⇒ $({2^{30}})$ = (2)? + 7
⇒ $({2^{7\; + \;23}})$ = (2)? + 7
⇒ ? = 23