CCommunity
Detailed solution?
Getting the first root by trial and error method?
Since the sum of the coefficients is not zero, 1 is not a root
Let x = -2
⇒ -8 + 16 + 22 – 30 = 0
∴ -2 is or (x + 2) is a factor
Dividing x3 + 4x2 – 11x – 30 by (x + 2)
Quotient = x2 + 2x – 15
⇒ x2 + 5x – 3x – 15 = 0
⇒ x (x + 5) – 3 (x + 5) = 0
⇒ (x – 3) (x + 5) = 0
Other factors are (x – 3) and (x + 5)
∴ (x + 2), (x – 3) and (x + 5) are the roots of the equation
Alternative method?
Since all the given options have only 3, 5 and 2 in different signs, this shortcut can be used
Product of the roots = -d/a = 30, positive
Sum of the roots = -b/a = -4
For product to be positive, either all terms are positive or two terms are negative
But since sum is negative, two terms has to be negative
Trying all thee combination of two roots to be negative
2 – 5 – 3 = -6
3 – 5 – 2 = -4
Second combination matches the condition –b/a = 4
∴ The roots are 3, -5 and -2
∴ The factors are (x – 3), (x + 5) and (x + 2)