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In the following question two equations are given. You have to solve these equations and determine relation between x and y.I. x2 – 526 = 1…

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In the following question two equations are given. You have to solve these equations and determine relation between x and y.
I. x2 – 526 = 1590
II. y2 + 1302 - 5398 = 0
  • AIf x > y
  • BIf x < y
  • CIf x ≤ y
  • DIf x ≥ y
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CCommunity
From the given data, we get

⇒ x2 – 526 = 1590

⇒ x2 = 1590 + 526 = 2116

⇒ x = √2116 = ±46

Also given that y2 + 1302 - 5398 = 0, we get

⇒ y2 – 4096 = 0

⇒ y2 = 4096

⇒ y = √4096 = ± 64

When x = 46 and y = 64, then x < y

When x = 46 and y = - 64, then x > y

When x = - 46 and y = 64, then x < y

When x = - 46 and y = - 64, then x > y

∴ Relationship cannot be determined