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A Shopkeeper promises to sell the cooking oil at x% profit, but he cheats while selling the oil by giving 20% less by weight. Find the value of x if he actually gains 35% profit.
- A12
- B10
- C8
- D6
Answer not set
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CCommunity
Suppose the cost price of 100L oil is Rs.100
Since he promises to sell the oil at x% profit, he promises that he is selling 100L oil for Rs. (100 + x)
But he cheats while selling the oil by giving 20% less by weight
⇒ Actually he sells (100 × 0.80) = 80L oil for Rs. (100 + x)
⇒ Selling price of 100L oil = Rs. [(100 + x)/80] × 100
Since his actual profit is 35%, he will be getting Rs. 135 for 100L oil
∴ [(100 + x)/80] × 100 = 135
⇒ 100 + x = 108
⇒ x = 8
Since he promises to sell the oil at x% profit, he promises that he is selling 100L oil for Rs. (100 + x)
But he cheats while selling the oil by giving 20% less by weight
⇒ Actually he sells (100 × 0.80) = 80L oil for Rs. (100 + x)
⇒ Selling price of 100L oil = Rs. [(100 + x)/80] × 100
Since his actual profit is 35%, he will be getting Rs. 135 for 100L oil
∴ [(100 + x)/80] × 100 = 135
⇒ 100 + x = 108
⇒ x = 8