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In an AC circuit, V and I are given by: V = 100 sin (100t) volts and I = 100 sin (100t + π/3) mA. The power dissipated in the circuit is
- A2.5 W
- B10 W
- C2500 W
- D10000 W
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CCommunity
V = 100 sin (100t) volts and
I = 100 sin (100t + π/3) mA
Phase difference = π/3
Power dissipated, $(P = {V_{rms}}{I_{rms}}\cos \phi)$
$(= \frac{{100}}{{\sqrt 2 }} \times \frac{{0.1}}{{\sqrt 2 }} \times \cos \frac{\pi }{3} = 2.5\;W)$
I = 100 sin (100t + π/3) mA
Phase difference = π/3
Power dissipated, $(P = {V_{rms}}{I_{rms}}\cos \phi)$
$(= \frac{{100}}{{\sqrt 2 }} \times \frac{{0.1}}{{\sqrt 2 }} \times \cos \frac{\pi }{3} = 2.5\;W)$