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If x is a prime number, LCM of x and its successive number would be
- Ax
- Bx + 1
- Cx(x + 1)
- Dx/(x - 1)
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CCommunity
We know that,
2, 3, 5, 7……. are prime numbers.
Let us solve this question by substituting the above prime numbers.
If x = 2 then (x + 1) = 3
⇒ LCM of 2 and 3 = 2× 3 = x × (x + 1) = 6
If x = 3 then (x + 1) = 4
⇒ LCM of 3 and 4 = 3 × 4 = x × (x + 1) = 12
∴ If x is a prime number, LCM of x and its successive number = x(x + 1)
2, 3, 5, 7……. are prime numbers.
Let us solve this question by substituting the above prime numbers.
If x = 2 then (x + 1) = 3
⇒ LCM of 2 and 3 = 2× 3 = x × (x + 1) = 6
If x = 3 then (x + 1) = 4
⇒ LCM of 3 and 4 = 3 × 4 = x × (x + 1) = 12
∴ If x is a prime number, LCM of x and its successive number = x(x + 1)