The number of votes, not casted for the PNC Party, increased by 25% in the National General Election over those, not casted for it in the p… — Answer & Discussion

The number of votes, not casted for the PNC Party, increased by 25% in the National General Election over those, not casted for it in the previous Assembly Polls, and the PNC Party lost by a majority twice as large as that by which it had won the Assembly Polls. If total 2,60,000 people voted each time, how many voted for the PNC Party in the previous Assembly Polls?

A1,40,000
B1,60,000
C2,00,000
D1,00,000

Answer not set

Join the discussion Report an error

Discussion 1

CCommunity16 May 2019

Total votes = 2,60,000

Let x voters voted against the party in the Assembly Polls.

Then, votes in favour = 260000 – x

Therefore, majority of votes by which party won in previous poll = 260000 – x – x = (260000 – 2x)

Next year, votes against the PNC party increase by 25%

So, votes against the party in general election = 1.25x

And votes polled in favour of the party = Total votes – Votes against = 260000 – 1.25x

Therefore, majority of votes by which party lost in general election

⇒ 1.25x – (260000 – 1.25x) = 2.5x – 260000

It is given that, PNC Party lost by a majority twice as large as that by which it had won the Assembly Polls,

∴ 2.5x – 260000 = 2(260000 – 2x)

⇒ 2.5x – 260000 = 2 × 260000 – 4x

⇒ 6.5x = 3 × 260000

⇒ x = 1,20,000

∴ No. of votes polled by the voters for the party in Assembly Polls for previous year

⇒ (2,60,000 – x)

⇒ (2,60,000 – 1,20,000)

⇒ 1,40,000