55
If (x - 2)2 + (y + 3)2 + (z - 15)2 = 0, then what is the value of x + y + z - 5?
- A5
- B9
- C15
- D20
Answer not set
Discussion 1
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CCommunity
Given, (x - 2)2 + (y + 3)2 + (z - 15)2 = 0
In order to satisfy this equation, each squared term is equal to zero
Hence, we get,
⇒ x - 2 = 0 ⇒ x = 2
⇒ y + 3 = 0 ⇒ y = -3
⇒ z - 15 = 0 ⇒ z = 15
∴ x + y + z - 5 = 2 - 3 + 15 - 5 = 9
In order to satisfy this equation, each squared term is equal to zero
Hence, we get,
⇒ x - 2 = 0 ⇒ x = 2
⇒ y + 3 = 0 ⇒ y = -3
⇒ z - 15 = 0 ⇒ z = 15
∴ x + y + z - 5 = 2 - 3 + 15 - 5 = 9