A, B and C are three students. A got 36% less marks than B and 16% more marks than C. If B got 145 marks, then what are the marks got by C?

Let C’s mark be y

From the problem’s statement

A’s marks can be given as 16% more than that of C

⇒ A’s mark = y × (1 + 16/100) = 1.16y ..…(i)

And also A’s marks can be given as 36% less than that of B

⇒ A’s mark = 145 × (1 – 36/100) = 92.8 From (i)

⇒ 1.16y = 92.8

⇒ y = 80

∴ the C’s marks are 80