Two motorcycles are moving towards each other with the speeds of 38 km/hr and 88 km/hr respectively. One second before the collision what w… — Answer & Discussion

Two motorcycles are moving towards each other with the speeds of 38 km/hr and 88 km/hr respectively. One second before the collision what will be the distance (in metres) between the two motorcycles if they are 126 km apart from each other?

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Discussion 1

CCommunity18 May 2019

Relative speed between the two motorcycles = (88 + 38) = 126 km/hr

The motorcycles will be colliding after a time which is given by: 126/126 = 1 hour = 3600 sec.

In m/sec = 126× 5/18 = 35 m/sec

In 3600 sec distance travelled by motorcycle 1 = 38000 meters

In 3600 sec distance travelled by motorcycle 1 = 88000 meters

After 3599 secs, distance covered by motorcycle 1 (d1) = 38000 – 38000/3600

After 3599 secs, distance covered by motorcycle 2 (d2) = 88000 – 88000/3600

So, the separation between 2 motorcycles is

= 126000 – (d1 + d2) = 126000 – 126000 + 126000/3600 = 35 meter