CCommunity
Given, two numbers are 35% and 50% lesser than a third number
Let the third number be ‘a’
1st number = a - 35% of a = 0.65a
2nd number = a - 50% of a = 0.5a
Let the % by which second number be enhanced be ‘c’%.
0.5a + c% of 0.5a = 0.65a
⇒ 0.5c/100 = 0.15
⇒ c = 30%
Alternate Method:
Given, two numbers are 35% and 50% lesser than a third number
Let's assume the third number be 100
1st$ number = 65
2nd$ number = 50
Required percenatge = ((65 - 50)/50) x 100
= 1500/50
= 30.