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Find the unit place digit in the given expression: (153)144 – (115)123–(111)510 + (216)25
- A1
- B5
- C6
- D3
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CCommunity
As, unit digit for a number ending in three and with power follow a cycle of 4
Unit digit of (153)144 = unit digit of (153)(144/4) = unit digit of (153)36 = 1
Now,
Unit digit of (115)123 = 5
Unit digit of (111)510 = 1
Unit digit of (216)25 = 6
∴ Unit digit of (153)144 – (115)123 – (111)510 + (216)25 = 1 – 5 – 1 + 6 = 1
Unit digit of (153)144 = unit digit of (153)(144/4) = unit digit of (153)36 = 1
Now,
Unit digit of (115)123 = 5
Unit digit of (111)510 = 1
Unit digit of (216)25 = 6
∴ Unit digit of (153)144 – (115)123 – (111)510 + (216)25 = 1 – 5 – 1 + 6 = 1