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If the side of square is increased by 6%, then what will be the percentage increase in its area?
- A13.5
- B12.04
- C12.12
- D12.36
Answer not set
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CCommunity
⇒ Let the side of the square be 100 cm
⇒ Area of the square = 100 × 100 = 10000 cm2
⇒ As side of the square is increased by 6%, the new vaue of side = 100 + (6% of 100) = 100 + 6 = 106 cm
⇒ New area of the square = 106 × 106 = 11236 cm2
⇒ Percentage increase in area = [(Final Area - Actual Area)/Actual Area] × 100%
⇒ [(11236 - 10000)/10000] × 100% = (1236/100)% = 12.36%
∴ Required Percentage = 12.36%
⇒ Area of the square = 100 × 100 = 10000 cm2
⇒ As side of the square is increased by 6%, the new vaue of side = 100 + (6% of 100) = 100 + 6 = 106 cm
⇒ New area of the square = 106 × 106 = 11236 cm2
⇒ Percentage increase in area = [(Final Area - Actual Area)/Actual Area] × 100%
⇒ [(11236 - 10000)/10000] × 100% = (1236/100)% = 12.36%
∴ Required Percentage = 12.36%