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If cos θ = 4/5, then (sec θ + cosec θ) =
- A7/5
- B15/12
- C35/12
- D12/5
Answer not set
Discussion 1
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CCommunity
Given,
cos θ = 4/5
So, sin θ = √(1 - (4/5)2) = √(25 - 16)/25 = √9/25 = 3/5
Thus, sec θ = 5/4
And, cosec θ = 5/3
∴ (sec θ + cosec θ) = 5/4 + 5/3 = (15 + 20)/12 = 35/12
cos θ = 4/5
So, sin θ = √(1 - (4/5)2) = √(25 - 16)/25 = √9/25 = 3/5
Thus, sec θ = 5/4
And, cosec θ = 5/3
∴ (sec θ + cosec θ) = 5/4 + 5/3 = (15 + 20)/12 = 35/12