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Two poles of the height 12 m and 17 m stand vertically upright on a plane ground. lf the distance between their feet is 12 m, find the distance between their tops.
- A11 m
- B12 m
- C13 m
- D14 m
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CCommunity
Distance between the feet (base) = 12 m
Length of the shorter pole = 12m
Length of the longer pole = 17 m
Difference in the lengths (height) = 17 - 12 = 5 m
The distance between the tops of the poles will form the hypotenuse of the right angle triangle.
Using Pythagoras theorem,
(Hypotenuse)2 = 122 + 52 = 144 + 25 = 169
⇒ Hypotenuse = 13
∴ Required distance = 13 m
Length of the shorter pole = 12m
Length of the longer pole = 17 m
Difference in the lengths (height) = 17 - 12 = 5 m
The distance between the tops of the poles will form the hypotenuse of the right angle triangle.
Using Pythagoras theorem,
(Hypotenuse)2 = 122 + 52 = 144 + 25 = 169
⇒ Hypotenuse = 13
∴ Required distance = 13 m