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A pyramid has a square base, whose side is 8 cm. If the height of pyramid is 16 cm, then what is the total surface area (in cm2) of the pyramid?
- A64(√17 + 1)
- B32(√13 + 1)
- C64(√3 + 1)
- D32(√5 + 1)
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CCommunity
Side of the square base = 8 cm and height of the pyramid = 16 cm
Slant height (l) of the pyramid needs to be evaluated,
⇒ l2 = (side/2)2 + (Height)2
⇒ l2 = 16 + 256 = 272
⇒ l = 4√17 cm
∴ Total surface area of the pyramid = (Base Area) + ½ × (Perimeter of base) × (Slant height)
⇒ 64 + ½ × 32 × 4√17
⇒ 64 + 64√17
⇒ 64(√17 + 1) cm2
Slant height (l) of the pyramid needs to be evaluated,
⇒ l2 = (side/2)2 + (Height)2
⇒ l2 = 16 + 256 = 272
⇒ l = 4√17 cm
∴ Total surface area of the pyramid = (Base Area) + ½ × (Perimeter of base) × (Slant height)
⇒ 64 + ½ × 32 × 4√17
⇒ 64 + 64√17
⇒ 64(√17 + 1) cm2