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If difference between the squares of two consecutive numbers is 45. Find the largest number.

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Let the number be x,

Then, consecutive number will be (x + 1)

Given that, (x + 1)2 – (x)2 = 45

Using (a + b)2 = a2 + 2ab + b2

⇒ x2 + 1 + 2x – x2 = 45

⇒ 2x = 45 - 1 = 44

⇒ x = 22

∴ The largest number is 23.