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20 boys do one fourth of a work in 25 days. How many more boys will be required to complete the remaining work in 50 days?
- A8
- B10
- C15
- D20
Answer not set
Discussion 1
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CCommunity
20 boys’ 25 days’ work = 1/4
⇒ 20 boys’ 1 day work = 1/4 × 1/25 = 1/100
⇒ 1 boy 1 day work = 1/20 × 1/100 = 1/2000
⇒ 1 boy 50 days’ work = 50 × 1/2000 = 1/40
⇒ Remaining work = 1 – 1/4 = 3/4
⇒ No. of boys required to do remaining work in 50 days = (3/4) / (1/40) = 30
∴ No. of more boys required = 30 – 20 = 10
⇒ 20 boys’ 1 day work = 1/4 × 1/25 = 1/100
⇒ 1 boy 1 day work = 1/20 × 1/100 = 1/2000
⇒ 1 boy 50 days’ work = 50 × 1/2000 = 1/40
⇒ Remaining work = 1 – 1/4 = 3/4
⇒ No. of boys required to do remaining work in 50 days = (3/4) / (1/40) = 30
∴ No. of more boys required = 30 – 20 = 10