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The minimum edge distance in member with rolled edge (for bolted hand cut connection) is approximately
- A1.5 × bolt diameter
- B1.5 × hole diameter
- C1.7 × bolt diameter
- D1.7 × hole diameter
Answer not set
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Specification for pitch of bolts or rivets
1. Minimum pitch and minimum gauge length
= {2.5 × nominal diameter of the bolt
2. Minimum end and edge distance
$(= \left\{ {\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{1.5 \times diameter\;of\;the\;bolt\;hole,for\;machine\;cut\;element}\\
{\;\;\;\;\;\;\;}
\end{array}}\\
{1.7 \times diameter\;of\;the\;bolt\;hole,for\;hand\;cut\;element}
\end{array}} \right.)$
3. Maximum end and edge distance
$(= \{ 12 \times t \times \epsilon,)$
Where, $(\epsilon = \sqrt {\frac{{250}}{{{f_y}}}})$
fy = yield stress
t = thickness of thinner plate
1. Minimum pitch and minimum gauge length
= {2.5 × nominal diameter of the bolt
2. Minimum end and edge distance
$(= \left\{ {\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{1.5 \times diameter\;of\;the\;bolt\;hole,for\;machine\;cut\;element}\\
{\;\;\;\;\;\;\;}
\end{array}}\\
{1.7 \times diameter\;of\;the\;bolt\;hole,for\;hand\;cut\;element}
\end{array}} \right.)$
3. Maximum end and edge distance
$(= \{ 12 \times t \times \epsilon,)$
Where, $(\epsilon = \sqrt {\frac{{250}}{{{f_y}}}})$
fy = yield stress
t = thickness of thinner plate