ExamCompetition Your Success, Our Mission
Login Register
Question discussion

The plan of a building is in the form of a rectangle with center line dimensions of outer walls as 12.6 m × 17.6 m. The thickness of the wa…

185188Medium 1 reply 4,170 views
18
The plan of a building is in the form of a rectangle with center line dimensions of outer walls as 12.6 m × 17.6 m. The thickness of the wall in superstructure is 40 cm, the plinth area of the building will be
  • A210 m2
  • B234 m2
  • C247 m2
  • D284 m2
Answer not set
Join the discussion Report an error

Discussion 1

0
CCommunity
Given:

Dimensions of outer walls = 12.6 m × 17.6 m.

Thickness of the wall = 40 cm = 0.40 m

Plinth area of the building = $(\left( {12.6 + \frac{{0.40}}{2} + \frac{{0.40}}{2}} \right) \times \left( {17.6 + \frac{{0.40}}{2} + \frac{{0.40}}{2}} \right))$

Plinth area of the building = (13 × 18) = 234 m2