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3 numbers whose average is 112, the first number is 1/6th the sum of other 2. What is the first number?
- A45
- B30
- C15
- D48
Answer not set
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CCommunity
? Average of three numbers is 112
This means sum of 3 numbers is = 112 × 3 = 336
Let the first number be X
Then X = (1/6) × (Sum of other two numbers) = (1/6) × (336 - X)
⇒ X + X/6 = 336/6
⇒ X = 336/7 = 48
∴ First number = 48
This means sum of 3 numbers is = 112 × 3 = 336
Let the first number be X
Then X = (1/6) × (Sum of other two numbers) = (1/6) × (336 - X)
⇒ X + X/6 = 336/6
⇒ X = 336/7 = 48
∴ First number = 48