CCommunity
The roots of a quadratic equation px2 + qx + r = 0 are equal only when q2 = 4pr
Given equation,
ax2 + x + b = 0
By comparing the above equation with px2 + qx + r = 0, we get
p = a;
q = 1
r = b
Thus putting the values in q2 = 4pr, we get
1 = 4ab
⇒ ab = 1/4