A trader bought two cows for Rs. 19,500. He sold one at a loss of 20% and the other at a profit of 15%. If the selling price of each cow is… — Answer & Discussion

A trader bought two cows for Rs. 19,500. He sold one at a loss of 20% and the other at a profit of 15%. If the selling price of each cow is the same, then what is their respective cost prices?

ARs. 10,000 and Rs. 9,500
BRs. 11,500 and Rs. 8,000
CRs. 12,000 and Rs. 7,500
DRs. 10,500 and Rs. 9,000

Answer not set

Join the discussion Report an error

Discussion 1

CCommunity27 May 2019

⇒ Let the cost of 1st cow be x and the cost of 2nd cow be y

⇒ Total cost of cow = 19,500 = x + y ------ 1

⇒ One cow sold at 20% loss and other at other at 15% profit

⇒ Selling at 20% loss (S. P1) = x - 20% of x

⇒ S. P1 = 0.8x

⇒ Selling at 15% profit (S. P2) = y + 15% of y

⇒ S. P2 = 1.15y

⇒ Selling Price is equal

⇒ 0.8x = 1.15y

⇒ x = (1.15/0.8) × y

⇒ x = 1.4375y

⇒putting the value of x in equation 1 we have

⇒ 1.4375y + y = 19,500

⇒ 2.4375y = 19,500

⇒ y = 19,500/2.4375

∴ y = 8000

⇒ then x = 19,500 - 8000

∴ x = 11,500