17
If x : y = 4 : 5, then (3x + y) : (5x + 3y)
- A3 : 5
- B5 : 3
- C17 : 35
- D35 : 17
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CCommunity
Given, x : y = 4 : 5
Let, x/y = 4/5 = k
⇒ x/4 = y/5 = k
∴ x = 4k, y = 5k
Given expression,
(3x + y) : (5x + 3y)
$(\begin{array}{l} = \frac{{3x + y}}{{5x + 3y}}\\ = \frac{{3 \times 4k + 5k}}{{5 \times 4k + 3 \times 5k}}\\ = \frac{{12k + 5k}}{{20k + 15k}} \end{array})$
= 17k/35k
= 17/35
= 17 : 35
Let, x/y = 4/5 = k
⇒ x/4 = y/5 = k
∴ x = 4k, y = 5k
Given expression,
(3x + y) : (5x + 3y)
$(\begin{array}{l} = \frac{{3x + y}}{{5x + 3y}}\\ = \frac{{3 \times 4k + 5k}}{{5 \times 4k + 3 \times 5k}}\\ = \frac{{12k + 5k}}{{20k + 15k}} \end{array})$
= 17k/35k
= 17/35
= 17 : 35