32
If cosecA - cotA = x, then the value of x is
- AsinA /(1 − cosA)
- B√[sinA /(1 + cosA)]
- CsinA /(1 + cosA)
- D√[sinA /(1 − cosA)]
Answer not set
Discussion 1
Log in or create a free account to reply and vote.
0
CCommunity
cosecA − cotA = x
1/sinA − (cosA/sinA) = x
(1 − cosA)/sinA = x
Multiplying and dividing by sinA,
(sinA – sinA.cosA)/sin2A = x
Sin2A + cos2A = 1
Hence, sin2A = 1 − cos2A
1 − cos2A = (1 + cosA)(1 − cosA)
Hence, x = (sinA– sinA . cosA)/(1 + cosA)(1 − cosA)
x = sinA(1 − cosA)/(1 + cosA)(1 − cosA)
x = sinA /(1 + cosA)
1/sinA − (cosA/sinA) = x
(1 − cosA)/sinA = x
Multiplying and dividing by sinA,
(sinA – sinA.cosA)/sin2A = x
Sin2A + cos2A = 1
Hence, sin2A = 1 − cos2A
1 − cos2A = (1 + cosA)(1 − cosA)
Hence, x = (sinA– sinA . cosA)/(1 + cosA)(1 − cosA)
x = sinA(1 − cosA)/(1 + cosA)(1 − cosA)
x = sinA /(1 + cosA)