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A 20 mm diameter mild steel rod is chosen for the construction work according to the calculation results. The weight of the above rod per meter length will be
- A0.75 kg
- B1.45 kg
- C2.50 kg
- D3.99 kg
Answer not set
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CCommunity
One cubic meter of mild steel weights about 7850 kg.
Therefore,
weight of the rod = volume of the rod × density of the material
weight of the rod = Cross – section of the rod × length of the rod × density of the material
Weight of the rod $(= {\rm{\;}}\frac{\pi }{4} \times {\left( {\frac{{20}}{{1000}}} \right)^2} \times 1 \times 7850 = 2.47\;{\rm{kg}})$
Therefore,
weight of the rod = volume of the rod × density of the material
weight of the rod = Cross – section of the rod × length of the rod × density of the material
Weight of the rod $(= {\rm{\;}}\frac{\pi }{4} \times {\left( {\frac{{20}}{{1000}}} \right)^2} \times 1 \times 7850 = 2.47\;{\rm{kg}})$